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# Larger Ideas Mathematics Geometry Solutions Section six Dating Inside Triangles

Larger Ideas Mathematics Geometry Solutions Section six Dating Inside Triangles

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## Big Details Mathematics Publication Geometry Respond to Key Chapter six Relationships Within this Triangles

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## Relationships Within Triangles Maintaining Analytical Skills

Explanation: The slope of the given line is $$\frac < 1> < 3>$$. Since the slope of the perpendicular line must be the negative reciprocal of the slope of the given line. The slope of the perpendicular line = -3 Substitute the values in y = mx + c 1 = -3(3) + c 1 = -9 + c c = 1 + 9 whiplr online c = 10 use the slope intercept form of a linear equation again substitute m, c y = -3x + 10

Explanation: The slope of the given line is -3. Since the slope of the perpendicular line must be the negative reciprocal of the slope of the given line. The slope of the perpendicular line = $$\frac < 1> < 3>$$ Substitute the values in y = mx + c -3 = –$$\frac < 1> < 3>$$(4) + c c = -3 + $$\frac < 4> < 3>$$ = $$\frac < -9> < 3>$$ = $$\frac < -5> < 3>$$ use the slope intercept form of a linear equation again substitute m, c y = $$\frac < 1> < 3>$$x + $$\frac < -5> < 3>$$ y = $$\frac < 1> < 3>$$x – $$\frac < 5> < 3>$$

Explanation: The slope of the given line is -4. Since the slope of the perpendicular line must be the negative reciprocal of the slope of the given line. The slope of the perpendicular line = $$\frac < 1> < 4>$$ Substitute the values in y = mx + c -2 = $$\frac < 1> < 4>$$(-1) + c c = -2 + $$\frac < 1> < 4>$$ = $$\frac < -8> < 4>$$ = $$\frac < -7> < 4>$$ use the slope intercept form of a linear equation again substitute m, c y = $$\frac < 1> < 4>$$x + $$\frac < -7> < 4>$$ y = $$\frac < 1> < 4>$$x – $$\frac < 7> < 4>$$

Explanation: At least means ? and no more than means < w ? -3 and w < 8 -3 ? w < 8

Explanation: more than means > and less than means < m > 0 and m < 11 0 < m < 11

Explanation: less than or equal to means ? and greater than means > s ? 5 or s > 2 2 < s ? 5